Question

Construct $∆\mathrm{DEF}$ such that $\mathrm{DE}=5\mathrm{cm}$, $\mathrm{DF}=3\mathrm{cm}$ and $\mathrm{m}\angle \mathrm{EDF}=90°$.

Answer 1

The steps for construction are given below:

Step 1: Draw a line segment $\mathrm{DF}=3\mathrm{cm}$.

Step 2: At point $\mathrm{D}$, draw a ray to make an angle of $90°$.

Step 3: Taking $\mathrm{D}$ as center, $5\mathrm{cm}$ as radius, draw an arc on the ray. Let the point where the arc intersects the ray be $\mathrm{E}$.

Step 4: Join $\mathrm{EF}$.

Hence, $∆\mathrm{DEF}$ obtained is the required right angled triangle.