Question

Construct $\Delta ABC$ in which $BC=8cm$, $\angle B={45}^o$ and $AB-AC=3.5$ cm.

Answer 1

R.E.F image

Construct a triangle ABC in Which $BC=8cm,\angle B={45}^{\circ }$ and $AB-AC=3.5$

cm.

Solution:

Given: In $\angle ABC,BC=8cm,\angle B={45}^{\circ }$ and $AB-AC=3.5cm$.

Required: To construct the triangle ABC.

Steps of construction:

1. Draw the base $BC=8cm.$

2. At the point B make an angle $CBX={45}^{\circ }.$

2. At the point B make an angle $CBX={45}^{\circ }.$

3. Cut the line segment BD equal to $3.5cm$ from the ray BX.

4. Join DC.

5. Draw the perpendicular bisector, say $PQ$ of $DC$.

6. Let in intersect BX at a point A.

7. Join AC.

Then ABC is the required triangle.