Question

Construct $\Delta$ACD such that AC = 5.5 cm, CD = 5 cm, and AD = 5.5 cm. The measure of $\angle A$ is .

• A. 62°
• B. 54°
• C. 64°

Answer 1

The correct option is B 54°

Steps of construction:
Step 1: Draw line segment AC = 5.5 cm.
Step 2: With A as centre, cut an arc of radius 5.5 cm.
Step 3: With C as centre, cut an arc of radius 5 cm.
Step 4: Mark the point of intersection of the arcs drawn as D.
Step 5: Join A and D, and C and D.


From the above construction, measure $\angle A$ using protractor.
$\angle A$ = 54°