Question

Sort steps to construct quadrilateral ABCD with AB, BC, CD, AD, AC as 4 cm, 6 cm, 5.5 cm, 5 cm, 8 cm.

• A. $WithAascentre,\mathrm{draw}\mathrm{an}\mathrm{arc}ofradius5cm\mathrm{to}\mathrm{the}\mathrm{opposite}\mathrm{side}\mathrm{of}\mathrm{AC}.$
• B. $\mathrm{With}Cascentre,drawanarcofradius6cmandmarkthe\mathrm{point}\mathrm{of}\mathrm{intersection}withthearcdrawninstep2asB.\mathrm{Join}\mathrm{AB}\mathrm{and}\mathrm{CB}.$
• C. $\mathrm{With}Aascentre,\mathrm{draw}\mathrm{an}\mathrm{arc}ofradius4cm.$
• D. $\mathrm{Draw}a\mathrm{line}\mathrm{segment}\mathrm{AC}\mathrm{of}8\mathrm{cm}.$
• E. $WithCascentre,drawanarcofradius5.5\mathrm{cm}andmarkthepointofintersectionwiththearc\mathrm{drawn}\mathrm{in}\mathrm{step}4asD.\mathrm{Join}\mathrm{AD}\mathrm{and}\mathrm{CD}.$

Answer 1

The given quadrilateral ABCD can be drawn as follows:

Step 1: Draw a line segment AC of 8 cm.

Step 2: With A as centre, draw an arc of radius 4 cm.

Step 3: With C as centre, draw an arc of radius 6 cm and mark the point of intersection with the arc drawn in step 2 as B. Join AB and CB.

Step 4: With A as centre, draw an arc of radius 5 cm to the opposite side of AC.

Step 5: With C as centre, draw an arc of radius 5.5 cm and mark the intersection point with the arc drawn in step 4 as D. Join AD and CD.