Construct ΔXYZ in which XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm.

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Solution

The rough figure of this triangle is as follows.

The required triangle is constructed as follows.

(i) Draw a line segment YZ of length 5 cm.

(ii) Point X is at a distance of 4.5 cm from point Y. Therefore, taking point Y as centre, draw an arc of 4.5 cm radius.

(iii) Point X is at a distance of 6 cm from point Z. Therefore, taking point Z as centre, draw an arc of 6 cm radius. Mark the point of intersection of the arcs as X. Join XY and XZ.

XYZ is the required triangle.

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Similar questions

Question 1
Construct $Δ$ XYZ in which XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm.

△ X Y Z

X Y = 4.5 c m, Y Z = 5 c m

Z X = 6 c m

∆

∠

50^{°}

△ X Y Z

X Y = 4 c m, y z = 6 c m

Z X = 3 c m

Δ X Y Z

∠ Y = 45^{o}, ∠ Z = 90^{o} a n d X Y + Y Z + Z X = 13 c m

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