Construct $△$ LMN such that LM = 6.6 cm , $∠$ LMN = 65 $°$ and ND is median and ND = 5 cm.

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Solution

Steps of construction:
(i) Draw a line segment LM = 6.6 cm.
(ii) Through L, draw LX such that $∠$ MLX= 65 $°$ .
(iii) Draw LY $⊥$ LX.
(iv) Draw the perpendicular bisector of LM intersecting LY at O and LM at D.
(v) With O as the centre and OL as the radius, draw a circle.
(vi) The major arc LWM of the circle contains the vertical 65 $°$ .
(vii) With D as the centre, draw an arc of radius 5 cm meeting the circle at N and N'.
Thus, $△$ LMN or $△$ LMN' is the required triangle.

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△ L M N

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Construct a triangle LMN, given LM = 5 cm, MN = 6.8 cm and ∠LMN = 70°. Write the steps of construction.

∆

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$△ L M N \sim$ $△ X Y Z$ . In $△ L M N, L M = 6 c m, M N = 6.8 c m, L N = 7.6 c m$ and $\frac{L M}{X Y} = \frac{4}{5}$ ; Construct $△ X Y Z$ .

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