Question

Construct the graph and find the zeroes of the polynomial $x=8y-3$.

Answer 1

$x=8y-3$ -- (1)
$8y=x+3$
$y=\frac{x+3}{8}$
From equation (1) assume the value of $x$ and $y$ to satisfy the equation to zero.

Plotting $(-3,0),(0,0.375)$ and joining them, we get another straight line.
The graph of $x=8y-3$ intersect the $x$-axis at $(-3,0)$. Hence the zero of $x=8y-3$ is $(-3,0)$ as it intersects at $x$-axis at $(-3,0)$.