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Construction of a Triangle with SSS Criterion

Construct the...

Question

Construct the right angled ΔPQR, where m∠Q = 90°, QR = 8 cm and PR = 10 cm.

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Solution

A rough sketch of ΔPQR is as follows.

The steps of construction are as follows.

(i) Draw a line segment QR of length 8 cm.

(ii) At point Q, draw a ray QX making 90º with QR.

(iii) Taking R as centre, draw an arc of 10 cm radius to intersect ray QX at point P.

(iv) Join P to R. ΔPQR is the required right-angled triangle.

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Similar questions

Question 1
Construct the right angled $Δ$ PQR, where $∠$ Q = $90^{\circ}$ , QR = 8 cm and PR = 10 cm.

Q. Construct the right angled

Δ

∠

90^{\circ}

, QR = 8 cm and PR = 10 cm.

Δ

∠ Q = 90^{\circ}

, QR = 8 cm and PR = 10 cm is constructed. What would be the measure of PQ?

Q. Construct a right angled

Δ

PQR such that PQ = 6 cm, QR = 7 cm, and

∠ P = 90 °

. Find the length of side PR.

∆

∠

°

∠

°

and PQ + QR + PR = 10 cm.

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Construction of a Triangle with SSS Criterion

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