Construct triangle ABC in which BC = 5 cm, AB − AC = 2.8 cm and ∠B = 40°.

Open in App

Solution

Steps of construction:

Step I: Draw line segment BC = 5 cm and at point B, draw an angle of measure 40°, say ÐXBC.

Step II: Cut line segment BD = 2.8 cm (= AB − AC) from ray BX.

Step III: Join DC and draw the perpendicular bisector PQ of DC.

Step IV: Let it intersect BX at point A. Join AC. ΔABC is the required triangle.

Suggest Corrections

Similar questions

Construct a triangle ABC in which AB = 5 cm, BC = 5 cm and AC = 4.3 cm.

∠

45^{\circ}

Construct a triangle ABC in which BC is 5 cm, Angle B is $120^{\circ}$ and AB+AC=17cm

A B C

A B = 5 c m, ∠ A = 30^{\circ}

A C - B C = 2.5 c m

△ A B C

A B = 3 c m, B C = 4 c m

A C = 5 c m

Join BYJU'S Learning Program