Construct LMN in which base MN - 7 cm- - LMN - 75- and LM - LN - 9 cm-

Steps of construction: Step 1. Draw MN = 5 cm Step 2. Construct ∠ M = 75^∘ and produce it to Y Step 3. Cut off line segment MO = 9 cm on MY Step 4. Join NO. ...

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Byju's Answer

Standard VI

Mathematics

Construction of a Triangle with Given Perimeter and Two Base Angles

Construct LMN...

Question

Construct $△$ LMN in which base MN = 7 cm, $∠$ LMN = $75^{\circ}$ and LM + LN = 9 cm.

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Solution

Steps of construction:

Step 1. Draw MN = 5 cm

Step 2. Construct $∠ M = 75^{\circ}$ and produce it to Y

Step 3. Cut off line segment MO = 9 cm on MY

Step 4. Join NO.

Step 5. Draw a perpendicular bisector of NO such that it intersects MY at L

Step 6. Join LN.

Step 7. LMN is the required triangle.

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Similar questions

Q. Construct

△ L M N

in which base

M N = 7 c m

∠ L M N = 75^{\circ}

and

L M + L N = 9 c m .

Q. Construct

∆

LMN in base MN = 7 cm,

∠

LMN = 40

°

and LM

-

LN = 3cm.

$△ L M N \sim$ $△ X Y Z$ . In $△ L M N, L M = 6 c m, M N = 6.8 c m, L N = 7.6 c m$ and $\frac{L M}{X Y} = \frac{4}{5}$ ; Construct $△ X Y Z$ .

△

LMN

~

△

XYZ, In

△

LMN, LM = 6 cm, MN = 6.8 cm, LN = 7.6 cm and

\frac{LM}{XY} = \frac{4}{3}

Construct

△

XYZ

Q. Construct

∆

LMN, such that LM = 6.2 cm, MN = 4.9 cm, LN = 5.6 cm.

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Construct △ LMN in which base MN = 7 cm, ∠ LMN = 75∘ and LM + LN = 9 cm.

Steps of construction: Step 1. Draw MN = 5 cm Step 2. Construct ∠M=75∘ and produce it to Y Step 3. Cut off line segment MO = 9 cm on MY Step 4. Join NO. Step 5. Draw a perpendicular bisector of NO such that it intersects MY at L Step 6. Join LN. Step 7. LMN is the required triangle.

Construct $△$ LMN in which base MN = 7 cm, $∠$ LMN = $75^{\circ}$ and LM + LN = 9 cm.