Question

Construct $△PQR$ such that perimeter of $△PQR$ is $16cm$ and $\angle Q={90}^{\circ }$ and $QR=5cm.$

Answer 1

Steps of Construction:

1. Draw a line segment $QR=5cm$.

2. At $Q$, construct an angle of ${90}^{\circ }$.

3. Cut an arc $QD$ of $11cm(16-5=11).$

4. Draw perpendicular bisector of $DR$ which intersects $QD$ at $P$.

5. Join $P-R$. Then, $PQR$ is the required triangle.