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Question

Construct PQR such that perimeter of PQR is 16 cm and Q=90 and QR=5 cm.

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Solution

Steps of Construction:
1. Draw a line segment QR=5 cm.
2. At Q, construct an angle of 90.
3. Cut an arc QD of 11 cm(165=11).
4. Draw perpendicular bisector of DR which intersects QD at P.
5. Join PR. Then, PQR is the required triangle.

595607_457364_ans.png

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