Construction of Triangle Whose Perimeter and Ratio of the Sides Are Given
Construct ∆XY...
Question
Construct ∆XYZ, if its perimeter is 14 cm, XY = 5 cm and ∠X = 45°.
Open in App
Solution
Here, perimeter of ∆XYZ = 14 cm and one side XY = 5 cm
∴ YZ + XZ = 14 – 5 = 9 cm and ∠X = 45°.
Steps of Construction :
1. Draw a line segment XY = 5 cm.
2. Construct an ∠YXA = 45° with the help of compass and ruler.
3. From ray XA, cut off XB = 9 cm.
4. Join BY.
5. Draw perpendicular bisector of BY and let it intersect XB in Z.
6. Join ZY. Thus, ∆XYZ is the required triangle.