Question

$Constucta\Delta ABCinwhichBC=4.8cm,\angle B={45}^{\circ }and\angle C={75}^{\circ }Measure\angle A.$

Answer 1

ANSWER:

Steps of construction:
1. Draw a line segment BC = 4.8 cm.
2. Construct $\angle CBX$ = 45°.3. Construct $\angle BCY$ = 75°.
4. The ray BX and CY intersect at A.
Thus, △ ABC is the required triangle.
When we measure $\angle A$, we get $\angle A$ = 60°.