Contact angle of different liquids on pure glass surface are -1- -2 and -3 and their wettability are represented as w1- w2 and w3 respectively- If -1-2-3- then

We know, Lower the contact angle, higher the wettability. Given, θ_1 gt;θ_2 gt;θ_3 ∴ w_1 lt;w_2 lt;w_3 ...

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Standard XII

Physics

Surface Tension

Contact angle...

Question

Contact angle of different liquids on pure glass surface are $θ_{1}, θ_{2}$ and $θ_{3}$ and their wettability are represented as $w_{1}, w_{2}$ and $w_{3}$ respectively. If $θ_{1} > θ_{2} > θ_{3}$ , then

w_{1} > w_{2} > w_{3}

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w_{1} < w_{2} < w_{3}

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w_{1} = w_{2} = w_{3}

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None of these

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Solution

The correct option is B $w_{1} < w_{2} < w_{3}$
We know,
Lower the contact angle, higher the wettability.
Given, $θ_{1} > θ_{2} > θ_{3}$
$∴ w_{1} < w_{2} < w_{3}$

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Contact angle of different liquids on pure glass surface are θ1, θ2 and θ3 and their wettability are represented as w1, w2 and w3 respectively. If θ1>θ2>θ3, then

The correct option is B w1<w2<w3We know, Lower the contact angle, higher the wettability. Given, θ1>θ2>θ3 ∴w1<w2<w3

Contact angle of different liquids on pure glass surface are $θ_{1}, θ_{2}$ and $θ_{3}$ and their wettability are represented as $w_{1}, w_{2}$ and $w_{3}$ respectively. If $θ_{1} > θ_{2} > θ_{3}$ , then

The correct option is B $w_{1} < w_{2} < w_{3}$
We know,
Lower the contact angle, higher the wettability.
Given, $θ_{1} > θ_{2} > θ_{3}$
$∴ w_{1} < w_{2} < w_{3}$