Convert 1 mm of Hg into Pa- Take density of Hg-13-6-103 kg m-3 and g-9-8 m s-2- Let it be x Pa- Find - x40-where - - is step function

The correct option is A 3 We know that #160; P = ρ gh ρ = 13.6 ×10^3 kgm^ 3 g = 9.8ms^ 2 h = 10^ 3m P = #160;13.6 ×10^3 kgm^ 3 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Negative Exponents

Convert 1 m...

Question

Convert $1 m m$ of $H g$ into $P a$ . Take density of $H g = 13.6 \times 10^{3} k g m^{- 3}$ and $g = 9.8 m s^{- 2}$ . Let it be $x$ $P a$ . Find [ $\frac{x}{40}$ ].{where , [] is step function}

3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $3$
We know that $P = ρ g h$
$ρ = 13.6 \times 10^{3} k g m^{- 3}$
$g = 9.8 m s^{- 2}$
$h = 10^{- 3} m$
$P = 13.6 \times 10^{3} k g m^{- 3} \times 9.8 m s^{- 2} \times 10^{- 3} m$
$P = 133.28 k g m^{- 1} s^{- 2}$
$x = 133.28$
$\frac{x}{40} = 3.332$
$[\frac{x}{40}] = 3$

Suggest Corrections

Similar questions

Convert 1 mm of Hg into pascal. Take density of Hg = 13.6 $\times 10^{3}$ kg $m^{- 3}$ and g= 9.8 m $s^{- 2}$ .

Convert 1mm of Hg into Pascal. Take density of Hg =13.6×10³ kg m^-3 and g = 9.8 ms-2

Q. The relative density of mercury is

13.6

. Its density in S.I. unit is given as

X \times 10^{3} k g m^{- 3}

. Find

X

Water is flowing through a horizontal tube. The pressure of the liquid in the portion where velocity is 2 m/s is 2 m of Hg. What will be the pressure in the portion where velocity is 4 m/s?

Q. The density of mercury is

13.6 g / c m^{3}

.Estimate the b value.Atomic mass of Hg=200.

Join BYJU'S Learning Program

Convert 1mm of Hg into Pa. Take density of Hg=13.6×103kgm−3 and g=9.8ms−2. Let it be x Pa. Find [x40].{where , [] is step function}

The correct option is A 3We know that P=ρghρ=13.6×103kgm−3g=9.8ms−2h=10−3mP=13.6×103kgm−3×9.8ms−2×10−3mP=133.28kgm−1s−2x=133.28x40=3.332[x40]=3

Convert $1 m m$ of $H g$ into $P a$ . Take density of $H g = 13.6 \times 10^{3} k g m^{- 3}$ and $g = 9.8 m s^{- 2}$ . Let it be $x$ $P a$ . Find [ $\frac{x}{40}$ ].{where , [] is step function}

The correct option is A $3$
We know that $P = ρ g h$
$ρ = 13.6 \times 10^{3} k g m^{- 3}$
$g = 9.8 m s^{- 2}$
$h = 10^{- 3} m$
$P = 13.6 \times 10^{3} k g m^{- 3} \times 9.8 m s^{- 2} \times 10^{- 3} m$
$P = 133.28 k g m^{- 1} s^{- 2}$
$x = 133.28$
$\frac{x}{40} = 3.332$
$[\frac{x}{40}] = 3$