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Question

Convert the following complex numbers into polar form.
2+63i5+3i

A
2eiπ6
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B
eiπ4
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C
2eiπ3
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D
eiπ6
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Solution

The correct option is C 2eiπ3
2+63i5+3i
2+63i5+3i×53i53i
=(10+18)+(303+23)i28
28(1+i)28=1+i
2(12+i2)
=2(cosπ4+isinπ4)
=2eiπ4.

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