Convert the following into moles:
i) 12g of $O_{2}$ gas
ii) 20g of water
iii) 22g of ${C O}_{2}$
iv) 52g of helium

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Solution

Formula of mole:

$m o l e (n) = \frac{G i v e n m a s s}{M o l a r m a s s}$

$12 g$ of $O_{2} \Rightarrow \frac{12}{32} = \frac{3}{8} m o l$

$20 g$ of $H_{2} O \Rightarrow \frac{20}{18} = \frac{10}{9} m o l$

$22 g$ of $C O_{2} \Rightarrow \frac{22}{44} = 0.5 m o l$

$52 g$ of $H e \Rightarrow \frac{52}{4} = 13 m o l$

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Convert into mole.

(a) 12 g of oxygen gas

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