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Question

# One mole of a mixture of CO and CO2 requires exactly 20 g of NaOH to convert all the CO2 into Na2CO3. How many more grams of NaOH would it require for conversion into Na2CO3 if the mixture (one mole) is completely oxidised to CO2?

A
60 g
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B
80 g
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C
40 g
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D
20 g
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Solution

## The correct option is A 60 gLet moles of CO =xSo, moles of CO2 =1−xNow, 2NaOH+CO2→Na2CO3+H2O2 moles of NaOH will react with 1 mole of CO2So, 20g NaOH = 0.5moles NaOH will react with 14=0.25 moles of CO2 Therefore, x=0.75 moles of CONow, On oxidation CO+12×O2→CO2CO(0.75moles)→CO2(0.75moles)Total moles of of CO2 = (0.25 + 0.75)moles = 1 molesTherefore, 1 mole of CO2 will react with 2 moles of NaOH i.e it will require (40×2)=80g of NaOH So, 60g more is required.Hence, the correct option is A

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