1
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Question

# 0.8 mole of a mixture of CO and CO2 requires exactly 40 gram of NaOH in solution for complete conversion of all the CO2 into Na2CO3. How many moles more of NaOH would it require for conversion into Na2CO3, if the mixture (0.8 mole) is completely oxidised to CO2:

A
0.2
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B
0.6
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C
1
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D
1.5
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Solution

## The correct option is B 0.6 2NaOH+CO2→Na2CO3+H2O Molar ratio 2 : 1 40 g NaOH=1 mole NaOH=12 mole CO2 (According to molar ratio) Total mixture of (CO+CO2)=0.8 mole → 2CO+O2→2CO2 shows us that the ratio of CO:CO2 is 1:1. Therefore, if mixture was completely oxidized then there would be 0.8 mole CO2 in total. → Of 0.8 mole we have already used 0.5 mole → We have 08−0.5=0.3 mole CO2 1 mole CO2→2 moles NaOH ∴ 0.3 moles CO2→0.6 moles NaOH

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