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Question

# 1 mole of mixture of CO and CO2 requires exactly 28g KOH in solution for complete conversion of all the CO2 into K2CO3 . How much amount more of KOH will be required for conversion into K2CO3 if one mole of mixture is completely oxidized to CO2.

A
112 g
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B
84 g
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C
56 g
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D
28 g
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Solution

## The correct option is B 84 gCO+12O2→CO2CO2+2KOH→K2CO3+H2OMoles of KOH =2856=0.50.lt corresponds to 0.25 moles of CO2.Hence, moles of CO=1−0.25=0.75 moles of CO2 formed.Moles of KOH required = 2×0.75=1.5mass of KOH required =1.5×56=84g.84 gm more KOH required.Therefore, option B is correct.

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