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Question

# One mole of a mixture of CO and CO2 requires exactly 20 g of NaOH in solution for complete conversion of all the CO2 into Na2CO3. If the mixture (one mole) is completely oxidised to CO2, then weight of NaOH to be used is:

A
60 g
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B
80 g
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C
40 g
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D
20 g
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Solution

## The correct option is D 80 g2NaOH+CO2→Na2CO3+H2O80 g of NaOH (2 moles of NaOH) required to convert 44g of CO2 (1 mole of CO2)If 20g of NaOH (12 mole) was used, then there was 11g of CO2 (14 mole) in mixture.∴ Mole of CO in mixture = 34If this CO is completely oxidised to CO2 then, mole of CO2 formed = 34∴ Total moles of CO2 = 14 + 34 = 1∴ Moles of NaOH required =2 × moles of CO2 = 2 × 1 = 2∴ Weight of NaOH required = 2 × 40 = 80 g

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