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Periodic Trends

copper having...

Question

copper having electronic configuration 2,8,18,1 exhibits variable valency.Give a reason for the same and name the compound cucl and cucl₂

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Solution

$C o p p e r h a s e l e c t r o n i c c o n f i g u r a t i o n o f 2, 8, 18, 1 . T h a t i s i t h a s o u t e r e l e c t r o n i c c o n f i g u r a t i o n a s 3 d^{9} 4 s^{2} . B u t d u e t o s t a b i l i t y i t e x i s t s w i t h 3 d^{10} 4 s^{1} c o n f i g u r a t i o n . S o i t l o s e s e i t h e r 1 o r 2 o u t e r e l e c t r o n s a n d e x h i b i t v a r i a b l e v a l e n c y a s 1 o r 2 C u C l i s c o p p e r (I) c h l o r i d e a n d i t s n a m e i s c u p r o u s c h l o r i d e . C u C l_{2} i s c o p p e r (I I) c h l o r i d e a n d i t s n a m e i s c u p r i c c h l o r i d e .$

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Similar questions

Q. Give reasons why copper exhibits variable valency.

Q. Copper forms two chlorides

C u C l

C u {C l}_{2}

.
(a) Identify the copper ions in these compounds?
(b) What is the valency of copper in each of these compounds?
(c) By writing the sub-shell electronic configuration of copper, find out a sub-shells from which the electrons are lost to form these ions.
(d) Write the period and group to which copper belongs.
(Hint: Atomic number of copper

= 29

M^{n +}

d^{4}

valence electronic configuration combines with three bidentate ligands to form a complex compound. Assuming

△ a > p

:
(i) Write the electronic configuration of

d^{4}

ion.
(ii) What type of hybridisation will

M^{n +}

ion has?
(iii) Name the type of isomerism exhibited by this complex.

Q. Members of the ______ have the similar electronic configuration of the valence shell and thus show the same valency.

C u

exhibits two types of valencies

{C u}^{+}

{C u}^{+ +}

. When chlorine reacts with copper why only

C u {C l}_{2}

{C u}^{+ +}

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