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Action of Water on Calcium Carbide

Copper reacts...

Question

Copper reacts with $H {N O}_{3}$ to give $N O$ and ${N O}_{2}$ in molar ratio of $1 : 2$ .
$C u + H {N O}_{3} ⟶ . . . . . . + N O + {N O}_{2} + . . . . . .$
If true enter 1,if false enter 0.

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Solution

The balanced chemical reaction is as follows:
$7 C u + 20 H {N O}_{3} \to 7 C u {({N O}_{3})}_{2} 2 {N O}_{2} + 4 N O + 10 H_{2} O$

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N O_{2}

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[C u^{2 +}] = 0.1 M

P_{N O} = P_{N O_{2}} = 10^{- 3}

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E_{C u^{2 +} | C u}^{\circ} = + 0.34 V, E_{N O_{3}^{-} | N O}^{\circ} = + 0.96 V, E_{N O_{3}^{-} | N O_{2}}^{\circ} = + .79 V

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S t a t e m e n t

H B r

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