Question

Correct order of bond angle is

• A. ${(}^{.}C{H}_3)>{(}^{.}C{F}_3)$
• B. $C{H}_3^{-}>C{H}_3^{+}$
• C. $C{H}_4>C{F}_4$
• D. $C{H}_4>{(}^{.}C{H}_3)$

Answer 1

The correct option is A ${(}^{.}C{H}_3)>{(}^{.}C{F}_3)$

Most electronegative F increases the p-character in the $C-F$ bond. Greater the p-character smaller the bond angle.
${}^{.}C{F}_3$ has smaller bond angle than ${}^{.}C{H}_3$

$C{H}_3^{+}$ and ${}^{.}C{H}_3$ are $s{p}^2$ hybridized and have trigonal planar shape.
$C{H}_3^{-}$ will be $s{p}^3$ hybridized
$C{H}_4$ and $C{F}_4$ are regular tetrahedral shape