Correct order of free radical allylic substitution of following is :- (1)CH3–CH=CH2 (II)(CH3)2CH-CH=CH2 (3)Ph–CH2–CH=CH2 (1) I > II > III (2) III > I > II (3) III > II > I (4) I > III > II

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Arrange the following compounds in decreasing order of reactivity with Br2

CH2=CH2 (I), CH ≡ CH (II), CH2=CHCl (III)

Arrange the following compounds in decreasing order of reactivity with $B r_{2}$

$C H_{2} = C H_{2} (I), C H \equiv C H (I I), C H_{2} = C H C l (I I I)$

Q. Place the following in the correct order of acidic nature

C H \equiv C - C O O H; C H_{2} = C H - C O O H; C H_{3} C H_{2} C O O H

(I) (II) (III)

Q. Basic strength of

C H I \equiv ⊖ C, C H_{2} = I I ⊖ C H, C H_{3} - I I I ⊖ C H_{2}

will be in order

$C H_{3} O - C H = C H - N O_{2}$	$I$
$C H_{2} = C H - N O_{2}$	$I I$
$C H_{2} = C H - C l$	$I I I$
$C H_{2} = C H_{2}$	$I V$

Which of the following is the correct order of

C = C

bond lengths among these compounds?

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