Question

Correct order of freezing point of given solution
I. 0.1 M glucose II. 0.2 M urea
III. 0.1 M $NaCl$ IV. 0.5 M ${CaCl}_2$

• A. I < II = III < IV
• B. I > II > III > IV
• C. III = II < IV < I
• D. IV > II > III > I

Answer 1

The correct option is A I < II = III < IV

$\left(I\right)$ $0.1M$ Glucose $\Rightarrow$ It will not be dissociated in solution, so final concentration will be $0.1M$.

$\left(II\right)$ $0.2M$ Urea $\Rightarrow$ It will also not be dissociated; final concentration= $0.2M$

$\left(III\right)$ $0.1M$ $NaCl\Rightarrow$ It will dissociate into $N{a}^{+}$ & $C{l}^{-}$ to produce two ions. Final concentration= $0.1\times 2=0.2M$

$\left(IV\right)$ $0.5M$ $CaC{l}_2\Rightarrow$ Dissociate to produce $3$ ions. Final concentration= $0.5\times 3=1.5M$

Correct order is:- $IV>III=II>I$