Question

$\cos {11}^o-\cos 2^o$ $>$ 0

• A. True
• B. False

Answer 1

The correct option is B False

$\cos {11}^o-\cos 2^o>0$

Ref. image

we know that value of cos decreases with increase in $\theta$ from 0 to $\frac{\pi }{2}$

$\therefore \cos {11}^o$ is less then $\cos 2^o$

$\therefore \cos {11}^o-cos{2}^o$ should be can then zero

Hence given statement is false.