Cos 200cos 400cos 600cos 800-18a- Find a

cos 20^0cos 40^0cos 60^0cos 80^0=cos 20^0cos ( 60^0 20^0 )cos ( 60^0+20^0 )cos 60^0 nbsp; nbsp; nbsp; nbsp; =1/4cos ( 3× 20^0 )cos 60^0=1/4co ...

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Sum of Trigonometric Ratios in Terms of Their Product

cos 200cos 40...

Question

$cos 20^{0} cos 40^{0} cos 60^{0} cos 80^{0} = \frac{1}{8 a}$ . Find $a$

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Solution

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