Cos-cos-2-sin-sin-2- kcos2- -2- then k is equal to

The correct option is A 4LHS = (cos^2α + nbsp;cos^2β + 2cosα nbsp;cosβ) + nbsp;(sin^2α + nbsp;sin^2β nbsp;+ nbsp;2sinα nbsp;sinβ) = 2 + 2 ...

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Complex Numbers

cosα+cosβ2+si...

Question

$(cos α + cos β)^{2} + (sin α + sin β)^{2} =$ $k {cos}^{2} (\frac{α - β}{2})$ , then k is equal to

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