Cos- -sin- - -cos- -sin- - -cos-Sin- - is equal to

The correct option is A 0 cosα #160; sin(β γ )+cosβ #160; sin (α γ )+cosγ sin (α β ) = cosα (sinβ cosγ sinγ cosβ ) + cosβ (sinγ cosα ...

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Polar Representation of a Complex Number

cosα .sinβ -γ...

Question

$c o s α . s i n (β - γ) + c o s β . s i n (γ - α) + c o s γ . S i n (α - β)$ is equal to

0

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\frac{1}{2}

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cos α . cos β . cos γ γ

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Solution

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