Question

Coupons numbered $1,2,.........,25$ are mixed up and one coupon is drawn at random. What is the probability that the ticket has a number which is multiple of $2$ or $3$?

• A. $\frac{16}{25}$
• B. $\frac{1}{5}$
• C. $\frac{3}{5}$
• D. $\frac{12}{25}$

Answer 1

The correct option is A $\frac{16}{25}$

Total no. of outcomes, $n\left(S\right)=25$

The favorable outcomes $=2,3,4,6,8,9,10,12,14,15,16,18,20,21,22,24.$

$\Rightarrow$The no of favorable outcomes,n(E)=16

$\therefore Probability\left(P\right)=\frac{n\left(E\right)}{n\left(S\right)}=\frac{16}{25}$