Covalency of sulphur in $S O_{4}^{2 -}$ ion is:

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Solution

The correct option is D 6
The sum of the oxidation numbers in a polyatomic ion is equal to the charge on the ion. The oxidation number of the sulfur atom in the $S O_{4}^{- 2}$ ion must be $+ 6$ . For example, because the sum of the oxidation numbers of the atoms in this ion must equal -2.

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Similar questions

S O_{4}^{2} -

Find the difference in oxidation numbers of sulphur in the $(S O_{4})^{2 -}$ ion and $S O_{3}$ compound.

(H_{2} S O_{4})

S_{8}

(H_{2} S O_{4})

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