Cr 2 O 7 2- -14 H -6 l - 2 Cr 3- -3 H 2 O-3 I 2Which element is reduced-

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Oxidation and Reduction

Cr 2 O 7 2- +...

Question

${C r}_{2} O_{7}^{2 -} + 14 H^{\oplus} + 6 l^{⊖} ⟶ 2 {C r}^{3 +} + 3 H_{2} O + 3 I_{2}$
Which element is reduced?

C r

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H

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O

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I

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Solution

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Similar questions

{C r}_{2} O_{7}^{2 -} + {F e}^{2 +} + H^{\oplus} ⟶ {C r}^{3 +} + {F e}^{3 +} + H_{2} O

6 {F e}^{2 +} + 14 H^{\oplus} + {C r}_{2} O_{7}^{2 -} ⟶ 6 {F e}^{3 +} + 2 {C r}^{3 +} + 7 H_{2} O

{C r}_{2} O_{7}^{2 -} H^{+} - - \to C r

{C r}_{2} O_{7}^{2 -}

{C r}_{2} O_{7}^{2 +} (a q) + 14 H^{+} (a q) + 6 {F e}^{2 +} (a q) \to 6 {F e}^{3 +} (a q) + 2 {C r}^{3 +} (a q) + 7 H_{2} O (l)

{C r}_{2} O_{7}^{2 -}

H N O_{2}

{C r}_{2} O_{7}^{2 -} + 5 H^{+} + 3 H N O_{2} \to 2 {C r}^{3 +} + 3 N {O_{3}}^{-} + 4 H_{2} O

{C r}_{2} {O_{7}}^{2 -}

2.4 \times 10^{- 4}

m o l

L^{- 1}

s^{- 1}

H N O_{2}

{C r}^{3 +}

{C O}_{2}

H_{2} O

{C r O}_{4}^{2 -}

{C r}_{2} O_{7}^{2 -}

{C O}_{2}

(H_{2} {C O}_{3} ⇌ H^{+} + {H C O}_{3}^{-})

{C r O}_{4}^{2 -}

{C r}_{2} O_{7}^{2 -}

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