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Cartesian Product in 3D

Cr2SO43 solut...

Question

$C r_{2} (S O_{4})_{3}$ solution produce green colour with $N a_{2} O (e x c e s s)$ and yellow colour with $N a_{2} O_{2} (e x c e s s)$ .
If true enter 1 else 0.
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Solution

The correct option is A 1
$C r_{2} (S O_{4})_{3}$ solution produce green colour (due to presence of Cr(III)) with $N a_{2} O$ (excess) and yellow colour (due to presence of Cr(VI) as in $N a_{2} C r O_{4}$ ) with $N a_{2} O_{2}$ (excess)

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Q. (A) (yellow coloured solution) changes to light green coloured solution (B) on passing

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K_{4} [{F e (C N)}_{6}]

, (B) does not. Here,
(A) :

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Q. If true enter 1, else enter 0.

S O_{2}

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K_{2} C r_{2} O_{7}

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N H_{4} S C N

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Q. "Alkali metals dissolve in liquid ammonia to give green coloured solutions which upon standing slowly liberate

H_{2}

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{F e}^{2 +}

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