Question

$Cr{O}_5$ has oxidation number of $Cr$ as $+6$. This implies it has two peroxy linkages.
If true enter 1, else enter 0.

• A. 1

Answer 1

The correct option is A 1
$Cr{O}_5$ has oxidation number of $Cr$ as $+6$. This implies it has two peroxy linkages.
Let $x$ be the oxidation number of Cr in $Cr{O}_5$.
Since the overall
charge on the complex is $0$, the sum of oxidation states of all elements in
it should be equal to $0$.
Therefore, $x+(-2)+4(-1)=0$
or, $x=+6$
The structure is shown below: