Question

Oxidation number of chromium in $Cr{O}_2^{2+}$ is $+6$.
If true enter 1, else enter 0.

• A. 1

Answer 1

The correct option is A 1
Let $x$ be the oxidation number of Cr in $Cr{O}_2^{2+}$.
Since the overall
charge on the complex is $+2$, the sum of oxidation states of all elements in
it should be equal to $+2$.
Therefore, $x+2(2-)=+2$
or, $x=+6$
Thus, the oxidation number of Cr in $Cr{O}_2^{2+}$ is $+6$.