Question

Oxidation number of carbon in $(CN{)}_2$ is $+3$.
If true enter 1, else enter 0.

• A. 1

Answer 1

The correct option is A 1
Let $x$ be the oxidation number of C in $(CN{)}_2$.
Since the overall
charge on the compound is $0$, the sum of oxidation states of all elements in
it should be equal to $0$.
Therefore, $2(x+(-3\left)\right)=0$
or, $x=+3$
Hence, the oxidation number of C in $(CN{)}_2$ is $+3$.