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Question

Critical angle for light going from medium (i) to (ii) is θ. The speed of light in medium (i) is v, then the speed of light in medium (ii) is

A
v(1cosθ)
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B
vsinθ
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C
vcosθ
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D
v(1sinθ)
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Solution

The correct option is B vsinθ
Critical angle=θ
Speed of light in medium(i)=v
sinθ=1μ
μ=1sinθ
μ2μ1=v2v1
where, μ2=μ, μ1=1, v1=v
μ1=v2v
v2v1=1sinθ
v2=vsinθ


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