You visited us 1 times! Enjoying our articles? Unlock Full Access!

Stoichiometric Calculations

CrO5 reacts w...

Question

$C r O_{5}$ reacts with $H_{2} S O_{4}$ to give $C r_{2} {(S O_{4})}_{3}$ , $H_{2} O$ and $O_{2}$ . Moles of $O_{2}$ liberated by $1$ mole of $C r O_{5}$ in this reaction are :

2.5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.25

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.75

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 1.75
Reaction:
$4 C r O_{5} + 6 H_{2} S O_{4} \to 2 C r_{2} (S O_{4})_{3} + 7 O_{2} + 6 H_{2} O$

4 moles $C r O_{5}$ liberates 7 moles of $O_{2}$

So, $O_{2}$ is produced by one mole of $C r O_{5} = \frac{7}{4} = 1.75$ .

Hence, option D is correct.

Suggest Corrections

Similar questions

C r O_{5}

H_{2} S O_{4}

C r_{2} {(S O_{4})}_{3}

H_{2} O

O_{2}

O_{2}

1

C r O_{5}

O_{2}

C r O_{5}

C r O_{5} + H_{2} S O_{4} \to C r_{2} (S O_{4})_{3} + H_{2} O + O_{2}

C r O_{5} + H_{2} S O_{4} \to C r_{2} (S O_{4})_{3} + H_{2} O + O_{2}

C r O_{5}

O_{2}

C r O_{5} + H_{2} S O_{4} \to C r_{2} (S O_{4})_{3} + H_{2} O + O_{2},

O_{2}

C r O_{5}

C r O_{5} + H_{2} S O_{4} \to C r_{2} (S O_{4})_{3} + H_{2} O + O_{2}

C r O_{5}

O_{2}

Join BYJU'S Learning Program