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Question

Crystal field splitting energy (CFSE) for the complex [Fe(CN)4] is ____ ,when Δ>P.

A
2.0
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B
Δ+P
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C
2+P
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D
0
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Solution

The correct option is D 0
Tetrahedral complex, Δt>P
Strong ligand, but pairing does not take place.
CFSE =(0.6×2+0.4×3)t=0

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