Question

Crystal field stabilization energy of high spin $d^4$ octahedral complex is:

• A. $–0.6{\Delta }_0$
• B. $-1.8{\Delta }_0$
• C. $1.6{\Delta }_0+P$
• D. $-1.2{\Delta }_0$

Answer 1

The correct option is A

$–0.6{\Delta }_0$

High spin $d_4$ configuration

$\Rightarrow t_{2g}{e}_g$

$\therefore CFSE=3\times (–0.4)+1\times 0.6\Delta 0$

$=–1.2+0.6\Delta 0$

$=–0.6\Delta 0$