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Question

Crystal field stabilization energy for high spin d4 octahedral complex is:

A
1.2 Δo
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B
0.6 Δo
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C
0.8 Δo
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D
1.6 Δo
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Solution

Step 1:

We know that for high spin, d4=t32ge1g
CFSE=(0.4x+0.6y) Δo
where, x= Number of electrons occupying t2g orbitals
y= Number of electrons occupying eg orbitals

Step 2:
CFSE=(0.4×3+0.6×1) Δo
=(1.2+0.6) Δo=0.6 Δo


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