Question

$CsCl$ crystallizes in body centred cubic lattice. If 'a' is its edge length then which of the following expressions is correct?

• A. $r_{C{s}^{⨁}}+r_{C{I}^{\ominus }}=\frac{\sqrt{3}}{2}a$
  
• B. $r_{C{s}^{⨁}}+r_{C{I}^{\ominus }}=\sqrt{3}a$
• C. $r_{C{s}^{⨁}}+r_{C{I}^{\ominus }}=3a$
• D. $r_{C{s}^{⨁}}+r_{C{I}^{\ominus }}=\frac{3a}{2}$

Answer 1

The correct option is A $r_{C{s}^{⨁}}+r_{C{I}^{\ominus }}=\frac{\sqrt{3}}{2}a$


$CsCl$ type is BCC ionic compound structure in which sum of their ionic radii is $\frac{\sqrt{3}}{2}a$