$C u^{2 +}$ ions are coloured, but $Z n^{2 +}$ ions are colourless. Why?

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Solution

Configuration of $C u^{+ 2} - [A r] 3 d^{9} Z n^{+ 2} - [A r] 3 d^{10}$
Copper has an unpared electron which acts as a $F$ centre and allows electron transition in visible region importing color while $Z n^{+ 2}$ is having no unpaired electrons hence colorless.

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