Consider the following reaction which of the following statement is true for this cell reaction- Zn - Cu 2- Zn 2- Cu A- Zn is reduced to Zn 2- ionsB- Cu 2- ions are oxidized to CuC- Zn is oxidized to Zn 2- ionsD- Zn 2- ions are oxidized to Zn

The correct option is Zinc loses two electrons so it is oxidized to zinc ions. ...

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Electrolysis and Electrolytes

Consider the ...

Question

Consider the following reaction which of the following statement is true for this cell reaction.

(Zn + Cu²⁺ → Zn²⁺ + Cu)

Zn²⁺ions are oxidized to Zn

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Zn is reduced to Zn²⁺ ions

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Cu²⁺ ions are oxidized to Cu

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Zn is oxidized to Zn²⁺ ions

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For cell reaction, $Z n + C u^{2 +} \to Z n^{2 +} + C u,$ cell representation is

The cell representation of the given reaction is:
Zn(s) + Cu²⁺ → Zn²⁺ + Cu(s)

What is the oxidizing agent in the following redox reaction?

$Z n (s) + C u^{2 +} (a q) \to Z n^{2 +} (a q) + C u (s)$

Divide the following redox reactions into oxidation and reduction half reactions.

(i) $Z n + P b^{2} \to Z n^{2} + P b$

(ii) $Z n + C u^{2 +} \to Z n^{2} + C u$

(iii) $C l_{2} + 2 B r^{-} \to B r_{2} + 2 C l^{-}$

E_{1}, E_{2}, E_{3}

Z n | Z n_{1 M}^{2 +} | | C u_{0.1 M}^{2 +} | C u

Z n | Z n_{1 M}^{2 +} | | C u_{1 M}^{2 +} | C u

Z n | Z n_{0.1 M}^{2 +} | | C u_{1 M}^{2 +} | C u

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