Cu+(aq) is unstable in solution and undergoes simultaneous oxidation and reduction, according to the reaction 2Cu+(aq)⇌Cu2+(aq)+Cu(s) Choose correct E for above reaction if ECu2+/Cu=0.34V and Ecu2+/Cu+=0.15V
A
−0.38V
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B
+0.49V
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C
+0.38V
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D
−0.19V
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Solution
The correct option is D+0.38V From given data (From ΔG=−nEF) (i) Cu(s)⟶Cu2+(aq)+2e−⋅ΔG1=−2×(−0.34)×F (ii) Cu2+(aq)+e−⟶Cu+(aq)⋅ΔG2=−1×(0.15)F On addition Cu(s)⟶Cu+(aq)+e−⋅ΔG3=−1×E×E ΔG3=ΔG1+ΔG2 =(−2×−0.34×F)+(−1×0.15×F) =+0.68F−0.15F=0.53F or E=−0.53V
Reaction, 2Cu+(aq)⇌Cu2+(aq)+Cu(s) E= ? So, Cu+(aq)+e−⇌Cu(s),