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Cu| Cu +2 1M ...

Question

$C u ∣ ∣ {C u}^{+ 2} (1 M) ∣ ∣ ∣ ∣ {Z n}^{+ 2} (1 M) ∣ ∣ Z n$
A cell represented above should have emf:

positive

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negative

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zero

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cannot be predicted

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Solution

The correct option is A positive
According to reactivity series, Zinc is more reactive and prefer to stay in oxidised form in comparison to copper.
$∴$ the reaction is spontaneous
$∴$ the EMF of the cell should be positive.

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Similar questions

E_{c e l l}^{0} = 1.18 V for Z n (s) | Z n^{+ 2} (1 M) | | C u^{+ 2} (1 M) | C u (s)

C u^{+ 2}

[C u^{+ 2}]_{e q .}

10^{- X}, M

[T = 298 K, \frac{2.303 R T}{F} = 0.059]

In an electrochemical cell represented as,

Zn | Zn²⁺₍c₁₎ || Cu²⁺₍c₂₎| Cu

So in this cell,

a.Zn is oxidized

b.Zn is reduced

c.Cu is oxidized

d.Cu is reduced

Below given are emf of three galvanic cells, represented by $E_{1}$ , $E_{2}$ and $E_{3}$ . Which of the following is true?

I. $Z n | Z n^{2 +} (1 M) | | C u^{2 +} (1 M) | C u$

II. $Z n | Z n^{2 +} (0.1 M) | | C u^{2 +} (1 M) | C u$

III. $Z n | Z n^{2 +} (1 M) | | C u^{2 +} (0.1 M) | C u$

The cell representation of the given reaction is:
Zn(s) + Cu²⁺ → Zn²⁺ + Cu(s)

Z n ∣ ∣ {Z n}^{2 +} (a q) ∣ ∣ ∣ ∣ {C u}^{2 +} (a q) ∣ ∣ C u

{C u}^{2 +} + {2 e}^{-} ⟶ C u, E^{\circ} = + 0.35 V

{Z n}^{2 +} + {2 e}^{-} ⟶ Z n, E^{\circ} = - 0.763 V

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