Cu- - e- - Cu- E- - x1 volt Cu2- - 2e- - Cu- E- - x2 volt- then for Cu2- - e- - Cu- E- volt will be-

The correct option is C 2x_1 x_1 Cu^⊕ + e^ → Cu ; E^⊖_1 = x_1 V Cu^2+ + 2e^ → Cu ; #160;E^⊖_2 = x_2 VNet equation #160; ...

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Gibb's Energy and Nernst Equation

Cu⊕ + e- → Cu...

Question

$C u^{\oplus} + e^{-} \to C u, E^{⊖} = x_{1}$ volt
$C u^{2 +} + 2 e^{-} \to C u, E^{⊖} = x_{2}$ volt, then for
$C u^{2 +} + e^{-} \to C u, E^{⊖}$ (volt) will be:

x_{1} - 2 x_{2}

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x_{1} + 2 x_{2}

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x_{1} - x_{2}

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2 x_{1} - x_{1}

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Solution

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Similar questions

{C u}^{+} + e^{-} ⟶ C u, E^{o} = x_{1}

{C u}^{2 +} + {2 e}^{-} ⟶ C u, E^{o} = x_{2}

{C u}^{+} + e^{-} ⟶ {C u}^{+}, E^{o}

E

E^{\circ}

N i | N i^{2 +} | | C u^{2 +} | C u

N i^{2 +} + 2 e^{-} \to N i; E^{\circ} = - 0.25 v o l t

C u^{2 +} + 2 e^{-} \to C u; E^{\circ} = + 0.34 v o l t

[N i^{2 +}] = 1 M

[C u^{2 +}] = 10^{- 3} M)

C u^{2 +} + e^{-} \to C u^{+}; E^{\circ} = 0.15 v o l t

C u^{+} + e^{-} \to C u; E^{\circ} = 0.5 v o l t

C u^{2 +} + 2 e^{-} \to C u

C u^{2 +} + 2 e^{-} \to C u, E^{\circ} = 0.337 V

C u^{2 +} + e^{-} \to C u^{+}, E^{\circ} = 0.153 V

E^{\circ}

C u^{+} + e^{-} \to C u

C u^{2 +} + e^{-} \to C u^{\oplus}

E^{\oplus} = 1.77 V

C u^{2 +} + 2 e^{-} \to C u

E^{⊖} = - 0.34

E^{⊖}

C u^{\oplus} + e^{-} \to C u

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