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Nernst Equation

Cu + + e - ⟶ ...

Question

${C u}^{+} + e^{-} ⟶ C u, E^{o} = x_{1}$ volt ;
${C u}^{2 +} + {2 e}^{-} ⟶ C u, E^{o} = x_{2}$ volt, then for
${C u}^{+} + e^{-} ⟶ {C u}^{+}, E^{o}$ (volt) will be :

x_{1} - {2 x}_{2}

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x_{1} + {2 x}_{2}

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x_{1} - x_{2}

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{2 x}_{2} - x_{1}

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Solution

The correct option is D ${2 x}_{2} - x_{1}$
${C u}^{+} + e^{-} ⟶ C u; {Δ G}_{1} = - F E^{o} = {- F x}_{1}$
${C u}^{2 +} + {2 e}^{-} ⟶ C u; {Δ G}_{2} = - 2 F E^{o} = {- 2 F x}_{2}$
${C u}^{2 +} + e^{-} ⟶ {C u}^{+}; {Δ G}_{3} = - F E^{o}$
$Δ G_{3} = Δ G_{2} - Δ G_{1}; {- F E}^{o} = - 2 F x_{2} + {F x}_{1}$
$E^{o} = 2 x_{2} - x_{1}$

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Similar questions

C u^{\oplus} + e^{-} \to C u, E^{⊖} = x_{1}

C u^{2 +} + 2 e^{-} \to C u, E^{⊖} = x_{2}

C u^{2 +} + e^{-} \to C u, E^{⊖}

C u^{2 +} + 2 e^{-} \to C u; E^{o} = 0.337

C u^{2 +} + e^{-} \to C u^{+}; E^{o} = - 0.153

E^{o}

C u^{+} + e \to C u

E^{o}

C u^{2 +} + e^{-} \to C u^{+}

E^{o} = 0.15

C u^{2 +} + 2 e^{-} \to C u

E^{o} = 0.34

E^{o}

C u^{+} + e^{-} \to C u

{C u}^{2 +} + {2 e}^{-} \to C u, E^{o} = + 0.337 V

{C u}^{2 +} + e^{-} \to C u^{+} E^{o} = + 0.153 V

E^{0}

{C u}^{+} + e^{-} \to C u

C u^{2 +} + e^{-} \to C u^{+}

E^{o} = 0.15 V

C u^{2 +} + 2 e^{-} \to C u

E^{o} = 0.34 V

E^{o}

C u^{+} + e^{-} \to C u

C u^{+}

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